Question

please answer this question give me answer please​

Answer 1

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hope this helps u❣️

Answer 2

area of triangle by heron's formula:

√s(s-a)(s-b)(s-c)

Step-by-step explanation:

the one side of equilateral triangle =12 cm

heron's formula :

√s(s-a)(s-b)(s-c)

a,b,c are sides of triangle

s=semi-perimeter=a+b+c/2=12+12+12/2=18cm

area=√18(18-12)(18-12)(18-12)

=√18×6×6×6

=√3×6×6×6×6

=36√3 sq.cm

this was the area of equilateral triangle

now for isosceles triangle

area of triangle by heron's formula=

√s(s-a)(s-b)(s-c)

here s is the semi perimeter and a,b,c are the sides of triangle

let the two sides of triangle=12cm

and perimeter =30cm

an isosceles triangle two sides are equal

so a=b=12cm

perimeter= 30cm

and third side be x

12+12+x=30cm

24+x=30cm

x=30-24

x=6cm

now the semi perimeter =15cm

area of triangle by using heron's formula:

√s(s-a)(s-b)(s-c)

=√15(15-12)(15-12)(15-6)cm sq.

=√15×3×3×9cm sq.

=√5×3×3×3×3×3cm sq

=√3sq.×3sq×3×5cm sq

=3×3×√3×5cm sq

=9√15cm sq.

hope it will help us lot plz marek the answer as brainliest