Question

please answer this question guys​

Answer 1

Answer:

3 seconds

Step-by-step explanation:

Let AB is the tower and BD is the highway.

Now from triangle ADB,

tan30 = AB/BD

=> 1/√3 = AB/BD

=> AB = BD/√3    .............1

Again from triangle ACB

tan60 = AB/BC

=> √3 = AB/BC

=> AB = BC√3 ........2

From (1) and (2)

BD/√3 = BC√3

=> (BC + CD)/√3 = BC√3

=> BC + CD = BC√3*√3

=> BC + CD = 3BC

=> 3BC - BC = CD

=> 2BC = CD

=> BC = CD/2  

Since time taken by car to cover CD = 6 Second

So time taken by car to cover BC = 6/2 = 3 seconds

Therefore,

The time taken = 3 seconds.

Hope it helps!

Answer 2

Answer: can u pls mark me brainliest pls

3 seconds

Step-by-step explanation:

Let AB is the tower and BD is the highway.

Now from triangle ADB,

tan30 = AB/BD

=> 1/√3 = AB/BD

=> AB = BD/√3    .............1

Again from triangle ACB

tan60 = AB/BC

=> √3 = AB/BC

=> AB = BC√3 ........2

From (1) and (2)

BD/√3 = BC√3

=> (BC + CD)/√3 = BC√3

=> BC + CD = BC√3*√3

=> BC + CD = 3BC

=> 3BC - BC = CD

=> 2BC = CD

=> BC = CD/2  

Since time taken by car to cover CD = 6 Second

So time taken by car to cover BC = 6/2 = 3 seconds

Therefore,

The time taken = 3 seconds.

Hope it helps!

Step-by-step explanation: