Math, asked by gchandrahasa, 5 months ago

please answer this question . I need to submit it tomorrow it self​

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Answered by jeetmit4
0

Answer:

tanФ=5/12  now make an right angle triangle and mark Ф as any acute angle in it. write 5x as the side opposite Ф and 12x on the side adjacent to Ф (not the hypotenuse). the find hypotenuse by

√{(5x)²+(12x)²} = √{25x² + 144x²}=  √{169x²} = 13x

then, secФ= \frac{13x}{12x}= \frac{13}{12}

and, cosecФ=\frac{13x}{5x}=\frac{13}{5}

or, secФ+cosecФ= \frac{13}{5} +\frac{13}{12} = \frac{221}{60} = 73.666666......≈73.666666667

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