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Answers
Answer:
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Step-by-step explanation:
Let the original number of rupee notes be r and the number of 20p coins be c.
Then, r + 0.2c = 15. (A)
When she returned, she had r + 0.2r = 1.2r
We know that the last expression is 1/3 of the amount she started with, 15.
1.2r = 15/3 = 5. (B)
Hence r = 5/1.2 which is not a solution since r must be an integer.
Since 15 is approx what she had, we deduce that she must have had slightly more or less. We are guided by the principle that both r and c must be integers.
The closest integers to 5/1.2 are 4 and 5.
If the number of rupee notes she started and ended with r = 4, the amount she ended with is 1.2 of this amount or 4.8 rupees.
The total amount she started with was 3 times this amount, i.e. 14.4 rupees (1.2 x 4 x 3). She therefore had 10.4 rupees in 20p coins or 52 coins when she started.
If r = 5, she must have started with 18 rupees and she would have 13 rupees in 20p coins or 65 coins.
My preference is that she started with 14.4 rupees as this amount is much closer to 15 rupees than 18 rupees is.
She therefore started with r=4, c=52 which gives a total of 14.4 rupees. She returned with 1/3 of this amount or 4.8 rupees with 4 rupee notes and 4 20p coins.