Math, asked by educationmaster37, 11 months ago

please answer this question I will mark it brainlist answer​

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Answered by Anonymous
9

Given :

  • α and 1/α are zeroes of the polynomial : 4x² - 2x + (k - 4)

To Find :

  • Value of k.

Solution :

Compare the given polynomial with general form.

General form :

  • ax² + bx + c = 0

Values of variables :

  • a = 4
  • b = - 2
  • c = k - 4

✪ Since, we see that k is along with the value of variable c and we know c is used in the relation of products of roots, so let's use it.

Product of zeroes :

\mathtt{\dfrac{1}{\alpha}\:\times\:\alpha\:=\:{\dfrac{c}{a}}}

\mathtt{1\:=\:{\dfrac{(k-4)}{4}}}

\mathtt{4\:=\:(k-4)}

\mathtt{4\:+\:4\:=\:k}

\mathtt{k\:=\:8}

\large{\boxed{\mathtt{\red{Value\:of\:k\:=\:8}}}}

Answered by Uniquedosti00017
1

Answer:

the value of k is 8.

refer to the attachment for the solution.

if it helps you then please mark as brainliest.

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