Question

please answer this question.
, i will mark me as a brainlist ​

Answer 1

Let the numerator be x and the denominator be x + 3,

According to the question,

$\frac{3x}{(x + 3) + 20} = \frac{1}{8} \\ \\ \frac{3x}{x + 23} = \frac{1}{8} \\ \\ 8 \times 3x = x + 23 \\ \\ 24x - x = 23 \\ \\ 23x = 23 \\ \\ x = 1$

So, as x = 1, That's why,

Numerator = 1

Denominator = x + 3

= 1 + 3

= 4

$so \: \: the \: \: required \: \: number \: \: is \\ \frac{1}{4}$

Hope it helps