Math, asked by banujahara, 5 hours ago

please answer this question I will mark you as brilliant​

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Answers

Answered by bhowmick00
1

Step-by-step explanation:

question 1 option c is correct answer

Answered by MeghnaR
1

Answer:

1. (c) 75m

2. Perimeter of 1 display board = 2(l+b) = 2(3+2) = 2*6 = 12m

Perimeter of 5 display boards = 12*5 = 60m

Length of the remaining ribbon = 75-60 = 15m

3. All are Yes

4. Perimeter of 1 display board = 5*4 = 20m

Total length of the ribbon = 75m

No. of boards he can decorate = 75/20 = 3.75

This means that he can decorate 3 full boards and 3 sides of the fourth board.

5. Circumference of the circle = 2πr = 2*3.14*35 = 219.8cm

Total length of the ribbon = 75m = 7500cm

No. of circular pieces that can be decorated = 7500/219.8 = 34.12

Therefore fully 34 pieces can be decorated.

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