please answer this question I will mark you as brilliant
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question 1 option c is correct answer
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1. (c) 75m
2. Perimeter of 1 display board = 2(l+b) = 2(3+2) = 2*6 = 12m
Perimeter of 5 display boards = 12*5 = 60m
Length of the remaining ribbon = 75-60 = 15m
3. All are Yes
4. Perimeter of 1 display board = 5*4 = 20m
Total length of the ribbon = 75m
No. of boards he can decorate = 75/20 = 3.75
This means that he can decorate 3 full boards and 3 sides of the fourth board.
5. Circumference of the circle = 2πr = 2*3.14*35 = 219.8cm
Total length of the ribbon = 75m = 7500cm
No. of circular pieces that can be decorated = 7500/219.8 = 34.12
Therefore fully 34 pieces can be decorated.
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