Question

Please answer this question immediately​

Answer 1

∆AOB=∆ACB (BECAUSE ANGLE IN THE SAME SEGMENT ARE EQUAL)

So ∆ACB=110°

∆A+∆C+∆B=180° (sum of all three sides of a triangle is 180 degree)

20+110+∆B =180

∆B = 180-130

∆B = 50

So∆ABC=50°

∆OAC=20°

Answer 2

Answer:

anglecob=110

angleabc=20

angleacb=50

angleoac=70