Question

please answer this question immediately

Answer 1

BAC~ RPQ

Therefore... AB/RP=AC/PQ=BC/RQ and angle A= angle P and angle B= angle Rand angle C =angle Q.....

In triangle BAC and triangle RPQ... AD and PS ARE BISECTORS  : 90 DEGREE

In triangle BAD and triangle RPS

Angle B = Angle R [P.A]

Angle  ADB = Angle PSR [90]

Traingle BAD ~ Traingle RPS

BA/RP=AD/PS=BD/SR

BA/RP=AD/PS

AD/PS=AC/PQ=BC/RQ=AB/RP

ar[ABC]/ar[PQR]= AB^2/RP^2=AC^2/PQ^2=BC^2/RQ^2

ar[ABC]/ar[PQR]= AD^2/PS^2