Question

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Answer 1

Step-by-step explanation:

We have,

$log( \frac{ {a}^{2} }{bc} ) + log( \frac{ {b}^{2} }{ca} ) + log( \frac{ {c}^{2} }{ab} )$

$= log( {a}^{2} ) - log(bc) + log( {b}^{2} ) - log(ca) + log( {c}^{2} ) - log(ab)$

$= 2 log(a) - log(b) - log(c) + 2 log(b) - log(c) - log(a) + 2 log(c) - log(a) - log(b)$

$= 2 log(a) - 2 log(a) + 2 log(b) - 2 log(b) + 2 log(c) - 2 log(c)$

$= 0$

Answer 2

log(a^2/bc)+log(b^2/ac)+log(c^2/ab)

//log (a/b)=log(a)-log(b)//

log (a^2)-log(bc)+log(b^2)-log (ac)+log(c^2)-log (ab)

log(a^2)+log(b^2)+log (c^2)-(log(bc)+log(ac)+log (ab))

log (a^2 b^2 c^2)-log (bc ac ab)

log((a^2 b^2 c^2)/(a^2 b^2 c^2))

log1

=0

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