Question

Please answer this question immediately it urgent...

Answer 1

hence the given number is given shows arbitrary positive integer.

Answer 2

Let a be the positive odd integer which when divided by 6 gives q as quotient and r as remainder.

according to Euclid's division lemma
a=bq+r

a=6q+r

where , a=0,1,2,3,4,5
then,
a=6q
or
a=6q+1
or
a=6q+2
or
a=6q+3
or
a=6q+4
or
a=6q+5

but here,
a=6q+1 & a=6q+3 & a=6q+5 are odd.