Question

Please answer this question in detail form
please answer all the three questions properly and I'm gonna give 40 points

Answer 1

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THE ANSWER IS HERE,

3)

Two irrational numbers between 0.5 & 0.55

=> (i) 0.515005000...........

=> (ii) 0.525225222..........

Two rational numbers between 0.5 & 0.55

=> (i) 0.511

=> (ii) 0.542

4)

(i)

$= > \: \frac{7 + 3 \sqrt{5} }{7 - 3 \sqrt{5} }$

$= > \: \frac{7 + 3 \sqrt{5} }{7 - 3 \sqrt{5} } \times \frac{7 + 3 \sqrt{5} }{7 + 3 \sqrt{5} }$

$= > \: \frac{ ({7 + 3 \sqrt{5} )}^{2} }{ {7}^{2} - {(3 \sqrt{5}) }^{2} }$

$= > \: \frac{49 + 45 + 42 \sqrt{5} }{49 - 45}$

$= > \: \frac{94 + 42 \sqrt{5} }{4}$

$= > \: \frac{47 + 21 \sqrt{5} }{2}$


(ii )

$= > \frac{2 \sqrt{3} - \sqrt{5} }{2 \sqrt{2} + 3 \sqrt{3} }$

$= > \: \frac{2 \sqrt{3} - \sqrt{5} }{2 \sqrt{2} + 3 \sqrt{3} } \times \frac{3 \sqrt{3} - 2 \sqrt{2} }{3 \sqrt{3} - 2 \sqrt{2} }$

$= > \: \frac{18 + 2 \sqrt{10} - 3 \sqrt{15} - 4 \sqrt{6} }{27 - 8}$

$= > \: \frac{18 - 4 \sqrt{6} + 2 \sqrt{10} - 3 \sqrt{15} }{19}$



(iii)

$= > \: \frac{7 \sqrt{3} - 5 \sqrt{2} }{ \sqrt{48} + \sqrt{18} }$


$= > \: \frac{7 \sqrt{3} - 5 \sqrt{2} }{ \sqrt{48} + \sqrt{18} } \times \frac{ \sqrt{48} - \sqrt{18} }{ \sqrt{48} - \sqrt{18} }$


$= > \: \frac{7 \sqrt{144} - 7 \sqrt{54} - 5 \sqrt{96} + 5 \sqrt{36} }{48 - 18}$

$= > \: \frac{84 - 21 \sqrt{6} - 20 \sqrt{6} + 30 }{30}$

$= > \: \frac{114 - 41 \sqrt{6} }{30}$


6)

(i)
$= > \: 3 \sqrt{5} + ( - \sqrt{5} ) + 180$

$= > \: 3 \sqrt{5} - \sqrt{5} + 6 \sqrt{5}$

$= > \: 8 \sqrt{5} .$


(ii)


$= > \: \sqrt{54} + \sqrt{150}$

$= > \: 3 \sqrt{6} + 5 \sqrt{6}$

$= > \: 8 \sqrt{6} .$




:-)Hope it helps u.

Answer 2

Answer:

Major difference between binary fission and budding is that in budding there is an outgrowth from the parent individual producing a bud, which is identical to its parent individual, but in binary fission, there is no bud or outgrowth formation.