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both are 70deg
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RPC=QPD ........ given
let angles RPC and QPD be x.......(1)
hence, RPQ + RPC + QPD = 180°.......angles on linear pair
40°+x+x = 180°
40°+2x = 180°
2x= 180°-40°
2x=140°
x= 140°/2
x= 70°
hence, angles RPC = QPD = 70°
NQB = QPD........ corresponding angles
NQB = 70
RPC + ARP = 180°........ interior angles
70° + ARP = 180 °
ARP = 180°-70°
ARP= 110°
MRQ = ARP............ opposite angle
MRQ = 110°
hence, NQB = 70°
MRQ = 110°
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