Question

please answer this question in trial and error method​

Answer 1

Answer:

3

Step-by-step explanation:

(2m/3)-1=1

(2/m)=2

m/3=1

m=3

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Answer 2

Answer:

Step-by-step explanation:

By the trial and error method,

Let us assume m = 0

∴ 2m/3 -1 =1

=

⇒ 2×0/3 -1 =1

⇒0/3-1=1

⇒0/3-3/3=1

⇒-3/3=1

⇒-1≠ 1

∴ m is≠0

Let us assume m = 1

So,

⇒2m/3 -1= 1

⇒2×1/3 -1 =1

⇒2/3 -1 =1

⇒2/3 -3/3 =1 ( after taking the LCM)

⇒-1/3 ≠ 1

∴m ≠ 1

Let us assume m = -1

So,

⇒2m/3 -1 = 1

⇒2×-1/3 -1 = 1

⇒-2/3 -1 = 1

⇒-2/3 -3/3 =1 ( after taking LCM )

⇒-5/3 ≠ 1

∴ m ≠ -1

 Let us assume m = 2

So,

⇒2m/3  -1 = 1

⇒2×2/3 -1 = 1

⇒ 4/3 -1 =1

⇒4/3 - 3/3 = 1 (after taking the LCM)

⇒1/3 ≠ 1

∴ m ≠ 2

Let us assume m = -2

So,

⇒2m/3 -1 = 1

⇒2× -2/3 -1 =1

⇒-4/3 -1 =1

⇒-4/3 -3/3 = 1 ( after taking the LCM )

⇒-7/3≠1

∴ m ≠ -2

Let us assume m =3

So,

⇒2m/3 - 1 = 1

⇒2 ×3/3 - 1 = 1

⇒ 6/3 - 1 = 1

⇒6/3 -3/3= 1 ( after taking the LCM)

⇒3/3 = 1

⇒1 = 1

∴ LHS =RHS

∴ m = 3

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