Question

please answer this question it is very important by step by step both of them

Answer 1

Hey user

Here is your answer :-

${4}^{x - 2} - {2}^{x + 1} = 0 \\ \\ {4}^{x - 2} = {2}^{x + 1} \\ \\ { ({2}^{2} )}^{x - 2} = {2}^{x + 1} \\ \\ {2}^{2(x - 2)} = {2}^{x + 1} \\ \\ 2(x - 2) = x + 1 \\ \\ 2x - 4 = x + 1 \\ \\ 2x - x = 4 + 1 \\ \\ x = 5$

$\frac{ {3}^{ {x}^{2} } }{ {3}^{x} } = 9 \\ \\ {3}^{ {x}^{2} - x} = {3}^{2} \\ \\ {x}^{2} - x = 2 \\ \\ {x}^{2} - x - 2 = 0 \\ \\ {x}^{2} - 2x + x - 2 = 0 \\ \\ x(x - 2) + 1(x - 2) = 0 \\ \\ (x - 2)(x + 1) = 0 \\ \\ x - 2 = 0 \: \: \: \: \: \: \: \: or \: \: \: \: \: \: \: \: x + 1 = 0 \\ \\ x = 2 \: \: \: \: \: \: \: \: or \: \: \: \: \: \: \: x = - 1$

Thank you .

Answer 2

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