Math, asked by Anonymous, 8 months ago

please answer this question.....it is very urgent...... don't post irrelevant and unnecessary Answer here.......plsssss answer my question fast​

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Answers

Answered by Anonymous
2

Step-by-step explanation:

We have :

LHS:

\bold{ \huge{ \sqrt{ \frac{ \sec(a) - 1 }{ \sec(a) + 1 } }} + \sqrt{ \frac{ \sec(a) + 1 }{ \sec(a ) - 1 } }}

sec(a)+1

sec(a)−1

+

sec(a)−1

sec(a)+1

\bold{ \huge{ \frac{ \sqrt{ \sec(a) - 1} }{ \sqrt{ \sec(a + 1 } }} + \bold{ \frac{ \sqrt{ \sec(a) + 1} }{ \sqrt{ \sec(a) - 1 } }}}

sec(a+1

sec(a)−1

+

sec(a)−1

sec(a)+1

\bold{ \huge{ \frac{(sec \: a - 1) + (sec \: a + 1)}{ \sqrt{(sec \: a + 1)(sec \: a - 1)} }}}

(seca+1)(seca−1)

(seca−1)+(seca+1)

\bold{ \huge{ \frac{2sec \: a}{ \sqrt{ {sec }^{2}a - 1 } }}}

sec

2

a−1

2seca

\bold{ \huge{ \ \frac{2sec \: a}{ \sqrt{ {tan}^{2} a} }}}

tan

2

a

2seca

\bold{ \huge{ 2 \: sec \: a \times cot \: a}}2seca×cota

\bold{ \huge( \frac{2}{cos \: a}} {\bold{ \huge\times \frac{cos \: a}{sin \: a} )}}(

cosa

2

×

sina

cosa

)

\bold{ \huge{ \frac{2}{sin \: a}}}

sina

2

\bold{ \huge{2 \: cosec \: a}}2coseca

\bold{ \huge{ \color{red}{proved:-}}}proved:−

Answered by ItzDeadDeal
5

Answer:

Step-by-step explanation:

We have :

LHS:

\bold{ \huge{ \sqrt{ \frac{ \sec(a) - 1 }{ \sec(a) + 1 } }} + \sqrt{ \frac{ \sec(a) + 1 }{ \sec(a ) - 1 } }} </p><p>

\bold{ \huge{ \frac{ \sqrt{ \sec(a) - 1} }{ \sqrt{ \sec(a + 1 } }} + \bold{ \frac{ \sqrt{ \sec(a) + 1} }{ \sqrt{ \sec(a) - 1 } }}} </p><p>

</p><p>\bold{ \huge{ \frac{(sec \: a - 1) + (sec \: a + 1)}{ \sqrt{(sec \: a + 1)(sec \: a - 1)} }}}

\bold{ \huge{ \frac{2sec \: a}{ \sqrt{ {sec }^{2}a - 1 } }}} </p><p>

\bold{ \huge{ \ \frac{2sec \: a}{ \sqrt{ {tan}^{2} a} }}}  </p><p>

\bold{ \huge{ 2 \: sec \: a \times cot \: a}}

\bold{ \huge( \frac{2}{cos \: a}} {\bold{ \huge\times \frac{cos \: a}{sin \: a} )}}

\bold{ \huge{ \frac{2}{sin \: a}}} </p><p>

\bold{ \huge{2 \: cosec \: a}}

\bold{ \huge{ \color{red}{Proved:-}}}

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