please answer this question it is very very important tomorrow is my exam
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rhombus ABCD
given,
each side =10cm
one of the diagonal BD=16cm
let the diagonals intersect at O
we know tht, diagonals in a rhombus make 90degrees at the centre. we also know tht diagonals bisect each other..
so.. AO=OC and BO=OD
from triangle AOB, (AB)^2=(AO)^2+(OB)^2
(10)^2=(AO)^2+(8)^2
100=(AO)^2+64
AO^2=100-64
AO^2=36
AO=6cm
length of other diagonal= BD=AO+OC
6+6=12 cm
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TejaswiniS143:
i hope it helps!!
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