Question

please answer this question it's urgent ​

Answer 1

Answer:

a + 55° + 60° = 180° (sum of all sides of ∆ = 180°)

a + 115° = 180°

a = 180° - 115°

a = 65°

a + b = 90° (linear pair)

65° + b = 90°

b = 90° - 65°

b = 25°

60°+ 40°+(55°+c)=180° (sum of all sides of ∆=180°)

100°+ 55° + c = 180°

155° + c = 180°

c = 180° - 155°

c = 25°

Therefore, a = 65° , b = 25° , c = 25°

Answer 2

sum of interior angles of a triangle = 180°

In ∆ PQS ,

55° + 60° + a = 180°

115° + a = 180°

a = 180° - 115°

a = 65°

a + b = 180° ( linear pair )

65° + b = 180°

b = 180° - 65°

b = 115°

In ∆ PSR ,

40° + b+ c = 180°

40° + 115° + c = 180°

155° + c = 180°

c = 180° - 155°

c = 25°

Hence,

a = 65°

b = 115°

c = 25°

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