Question

Please answer this question (it's urgent).​

Answer 1

Answer:

Use the above formula...

I hope this might help you ☺

Answer 2

$\small{ \orange {\boxed {{\begin{array}{cc} \maltese \: \bf \: given \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bf \rightarrow \:capacitance \: \: \: C =0.1 \mu \: F = 0.1 \times {10}^{ - 6} \: F \\ \\\bf \rightarrow \:distance \: \: d = 0.1 \: mm = 0.1 \times {10}^{ - 3} \: m \\ \\ \bf \rightarrow \:area \: A = to \: find \\ \\ \red{\sf \: we \: know \: that }\\ \\ \pink{ \boxed{{\begin{array}{cc} \bf \: C = \frac{ \epsilon_0 \: A}{d} \\ \\ \bf \implies \: A = \frac{C \: d}{ \epsilon_0} \\ \\ \bf \implies \: A = \frac{0.1 \times {10}^{ - 6} \times 0.1 \times {10}^{ - 3} }{8.854 \times {10}^{ - 12} } \\ \\ \bf \implies \: A = 1.12 \: {m}^{2} \end{array}}}}\end{array}}}}}$