Please answer this question... It was in my today's Pre-Board II n I had lots of difficulties solving it... still couldn't arrive at any proper solution!
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area of triangle PQR= area of QOR+POR+POQ---(three triangle in one)
=> 189=42+24+2x+18+2x-----------(tangent of the circle)(area of triangle=bh/2
=> 189-84=4x
=>105/4=x
=>x=26.25 -----------(X IS PA AND PB)
=> PA=PB=26.25 -------------(TANGENT OF THE CIRCLE)
=> PQ=26.25+12=38.25CM
=> PR=26.25+9 = 35.25CM
=> 189=42+24+2x+18+2x-----------(tangent of the circle)(area of triangle=bh/2
=> 189-84=4x
=>105/4=x
=>x=26.25 -----------(X IS PA AND PB)
=> PA=PB=26.25 -------------(TANGENT OF THE CIRCLE)
=> PQ=26.25+12=38.25CM
=> PR=26.25+9 = 35.25CM
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faizaankhanpatp3bt9p:
hope this was helpful
can u plz xplain it in a bit more detail....
ya sure
lyk how u got those values lyk 2x n all!
plz...
here u go a bit edits
might help
thanx a lot....
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