Question

please answer this question
its urgent

Answer 1

Given: D is the midpoint of AB and P Point is any point on BC, CQ‖ PD
In Quadrilateral DPQC
Area (Δ DPQ) = Area (Δ DPC)
Add Area (Δ BDP) on both sides
We get,
Area (Δ DPQ) + Area (Δ BDP) = Area (Δ DPC) + Area (Δ BDP)
Area (Δ BPQ) = Area (Δ BCD) –1
D is the midpoint BC, and CD is the median
∴ Area (Δ BCD) = Area (Δ ACD) = 1/2 × Area (Δ ABC) –2
Sub –2 in –1
Area (Δ BPQ) = 1/2 × Area (Δ ABC) (∵Area (Δ BCD) = 1/2 × Area (Δ ABC))

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