Math, asked by zoyasadaf, 1 month ago

please answer this question mentioned in attachment​

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Answered by ankitakenganur555
0

Step-by-step explanation:

lhs=(sinA-cosA/sinA+cosA)+sinA+cosA/sinA-cosA)

=(sinA-cosA)^2+(sinA+cosA)^2/(cosA+sinA)(sinA-cosA)

=sin^2A+cos^2A-2sinAcosA+sin^2A+cos^2A+)2sinAcosA/sin^2A-cos^2A

1+1/sin^2A-(1-sin^2A)

=2/sin^2A-1+sin^2A

=2/2sin^2A-1.

Answered by bandanamaity741
1

Answer:

see this answer hope it will help you

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