please answer this question no 6.
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The answer here will be 120.
As there will always one school left so
one school can be left in 5 different ways.
Let's assume school number 1 is left so the remaining 4 school can be choosen in 24 number of ways.
_ 4x3x2x1
similarly if 2nd school is left then
4_3x2x1
so the answer will be
5x( 4x3x2x1) = 120
As there will always one school left so
one school can be left in 5 different ways.
Let's assume school number 1 is left so the remaining 4 school can be choosen in 24 number of ways.
_ 4x3x2x1
similarly if 2nd school is left then
4_3x2x1
so the answer will be
5x( 4x3x2x1) = 120
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