Question

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Answer 1

see tese two above attachment

Answer 2

Answer:

→ HEY MATE,

→ Step-by-step explanation:

→ solution :

→ Distance Travelled s  = 10m

→ Final velocity = , v = 0ms^-1

→ Acceleration due to gravity , g = 9.8 ms^-2

→ Acceleration of the object , a = -9.8 ms^-2 ( upward motion)

→ ( 1 ) →  v^2 = u^2 + 2as

→ 0 = u^2 + 2 × (-9.8ms^-2) × 10 m

→ -u^2 = -2 × 9.8 × 10 m^2s-^2

→ u = $\sqrt{196}$ m s ^-1

→ u = 14ms^-1

(2) u = 14ms^-1  solution

( 2 ) solution : v = u + at

                      0 = 14ms^-1 - 9.8 m s^-2 × t

                       t = 1.43s is the solution

Thus  ,

(1) Initial velocity , u = 14 m s^-1 , and

(2) Time taken , t = 1.43s

 

Thank you