Question

Please answer this question
no wrong answer ​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let the angle at which the transversal intersects the lines be θ

So, ∠BAD=θ,∠EBA=180−θ

OB bisects the ∠EBA and OA bisects the ∠BAD.

consider △AOB,∠BAO=θ/2

∠OBA= 1/2 (180−θ)=90− θ/2

∠BAO+∠OBA+∠BOA=180°

⟹90− θ/2+θ/2 +∠AOB=180

⟹∠AOB=90°

∴ the bisectors of internal angles on the same side of the transversal intersects at right angles

I hope this helps you!