please answer this question of trigonometry of class 10
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sinx=12/13=Perpendicular/hypoteneuse
perpendicular=12
hypoteneuse=13
base²+perpendicular²=hypoteneuse ²
base²=13²-12²=169-144=25
base=√25=5
cosx=base/hypoteneuse=5/13
tanx=sinx/cosx=(5/13)/(12/13)=5/12
now put values of all these in equation
perpendicular=12
hypoteneuse=13
base²+perpendicular²=hypoteneuse ²
base²=13²-12²=169-144=25
base=√25=5
cosx=base/hypoteneuse=5/13
tanx=sinx/cosx=(5/13)/(12/13)=5/12
now put values of all these in equation
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