Question

please answer this question only the expert able to answer this question​

Answer 1

$\textbf{\boxed{SOLUTION:-}}$

Let x be a multiple of 8,

then the other numbers will be (x+8) , (x+16)

According to the question.

The sum of three consecutive multiples of 8 is eight times the first two multiples of 6

The first two multiples of six are - 6 and 12

So,

x + (x+8) + (x+16) = 8(6+12)

x + x + 8 + x + 16 = 8(18)

3x + 24 =  144

3x = 144 - 24

3x = 120

x = $\frac{120}{3}$

x = 40

                                                               

$\mathfrak{Hence,\:the\:three\:multiples\:are:-}$

x = 40

x+8 = 40+8 = 48

x+16 = 40+16 = 56

The numbers are - 40,48,56