Question

please answer this question please​

Answer 1

Answer:

hey mate , the ans 70

Step-by-step explanation:

if AB is Parallel to CD, we can assume that EC is a transversal that intersect AB and CD

Let the point formed by intersection of transversal EC be O.

Then angle COB is equals to 110° Because corresponding angles are equal.

that is

ECD =COB=110

EOA AND COB are linear pairs , so

EOA +COB =180°

EOA +110 =180

EOA =180-110=70°

NOW in triangle AEO

angle A + angle x+ angle O =180(angle sum property of triangle)

40 + x + 70= 180

x= 180-110

= 70°

HOPE THIS HELPS

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THANK U

Answer 2

Answer:

x==70°

Step-by-step explanation:

Extension EC to F

∠EFB=∠ ECD=110 ( Corresponding angles)

SO ∠EFA=180-110=70

Now in ΔEAF

∠EFB=∠AEF+∠EAF

110=x+40

x=110°-40°=70°