Question

Please answer this question.
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Answer 1

Answer:

Thus volume occupied by 1 H2O mlecule is 2.99 ×10^-23 ml. The number of moles in 1 litre = 1000 / 18.02 = 55.5 moles. 1 mole of water = 6.022 x 10^23 molecules of water, So 55.5 moles of water = 55.5 x 6.022 x 10^23 = 3.34 x 10^25 molecules of water.

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Answer 2

Answer :-

solution a )

1 mole of water = 6.022 x 10^23 molecules of water, So 55.5 moles of water = 55.5 x 6.022 x 10^23 = 3.34 x 10^25 molecules of water. The gram molecular mass of water is 18.02. Thus volume occupied by 1 H2O molecule is 2.99 ×10-23 ml.

solution b)

As you know, density of water is 1 g/cm³

and molecular weight of water is 18g/mol , it means , 18g of water contains 6.023 × 10²³ molecules of it.

First of all we have to find volume of 1 mole of water

= mass/density = 18g/{1g/cm³} = 18 cm³

hence, volume of 1 mole of water = 18cm³ = 18 × 10⁻⁶ m³

∵ 1 mole of water = 6.023 × 10²³ molecules of water

∴ volume of 6.023 × 10²³ molecules of water = 1.8 × 10⁻⁵ m³

⇒ volume of 1 Molecule of water = 1.8/6.023 × 10⁻⁵⁻²³ m³

= 0.2988 × 10⁻²⁸ m³

Let radius of water molecule is r

Then, volume of 1 Molecule of water = 4/3 πr³

∴ 4/3 πr³ = 0.2988 × 10⁻²⁸ m³

⇒r³ = 0.2988 ×3/4π × 10⁻²⁸

⇒r = 0.1925 × 10⁻⁹ m = 0.1925 nm.

Hence, answer should be 0.1925 nm

hope it helps you..