Math, asked by rachanakrishna, 4 months ago

please answer this question please dears ​

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Answered by Asterinn
6

 \large \longrightarrow \rm \lim \limits_{ \rm x \rightarrow2} \bigg( \dfrac{1}{x - 2}  -  \dfrac{4}{ {x}^{3} - 2 {x}^{2}  }  \bigg) \\  \\  \\ \large \longrightarrow \rm \lim \limits_{ \rm x \rightarrow2} \bigg( \dfrac{1}{x - 2}  -  \dfrac{4}{  {x}^{2} ({x}^{} - 2)}  \bigg) \\  \\  \\ \large \longrightarrow \rm \lim \limits_{ \rm x \rightarrow2} \bigg( \:  \dfrac{ {x}^{2}  - 4}{  {x}^{2} ({x}^{} - 2)}   \: \bigg)\\  \\  \\ \large \longrightarrow \rm \lim \limits_{ \rm x \rightarrow2} \bigg( \:  \dfrac{ {x}^{2}  - {2}^{2}  }{  {x}^{2} ({x}^{} - 2)}   \: \bigg)\\  \\  \\ \large \longrightarrow \rm \lim \limits_{ \rm x \rightarrow2} \:  \dfrac{ ({x}^{}  - {2}^{} ) (x + 2)}{  {x}^{2} ({x}^{} - 2)}   \: \\  \\  \\ \large \longrightarrow \rm \lim \limits_{ \rm x \rightarrow2} \:  \dfrac{ \cancel{({x}^{}  - {2}^{} }) (x + 2)}{  {x}^{2} \cancel{ ({x}^{} - 2)}}   \: \\  \\  \\ \large \longrightarrow \rm \lim \limits_{ \rm x \rightarrow2} \:  \dfrac{ x + 2}{  {x}^{2} }   \: \\  \\  \\ \large \longrightarrow \rm  \dfrac{2 + 2}{ {2}^{2} }  \\  \\  \\ \large \longrightarrow \rm \dfrac{4}{ 4} \\  \\  \\ \large \longrightarrow \rm 1


rachanakrishna: Hello Kashyap your anwer is really brilliant I posted a qn please answer that one also please......
divyasrithiruselvam: i m not kashyap
rachanakrishna: the above answer is by whom
rachanakrishna: is that Kashyap
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