Question

Please answer this question....please of all parts.....


Please it's my request....

Please guys....​

Answer 1

Answer:

22)a+b=12 and ab=27,Find a³+b³

Hey !!!

a + b = 12 |given|

ab = 27

•°• we know that

a³ + b ³ = (a + b ) ( a² + b² - ab )

and , ( a + b ) ²- 2ab = a² + b²

so , a³ + b³= ( a + b ){ ( a + b )² - 3ab }

hence , a³ + b³ = 12{12²- 3 ×27 } ✔ putting the given value

=> 12 { 144- 3×27 }

=> 12×63

= > 756 Answer

a³ + b³ = 756 Answer

___________________

Answer 2

Answer:

22.

a+b=12

ab=27

a^3+b^3= (a+b)(a^2+b^2-2ab)

{(a+b)^2=a^2+b^2+2ab

(12)^2=a^2+b^2+2×27

144=a^2+b^2+54

144-54=a^2+b^2

90=a^2+b^2}

putting these value in upper formula

a^3+b^3=12(90-2×27)

a^3+b^3=12×36

=436

hope this will help you