please answer this question please.... question no. 20 please answer right.
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(19)
Given f(x) = x^3 - 2mx^2 + 16
Given that x + 2 is a factor of f(x).
= > x + 2 = 0
= > x = -2.
Plug x = -2 in f(x), we get
= > (-2)^3 - 2m(-2)^2 + 16 = 0
= > -8 - 8m + 16 = 0
= > 8 - 8m = 0
= > 8 = 8m
= > m = 1.
Therefore the value of m = 1.
(20)
Given f(x) = x^5 - 4a^2x^3 + 2x + 2a + 3.
Given that x + 2a is a factor of f(x).
= > x + 2a = 0
= > x = -2a.
Plug x = -2a in f(x), we get
= > f(-2a) = (-2a)^5 - 4a^2(-2a)^3 + 2(-2a) + 2a + 3 = 0
= -32a^5 + 32a^5 - 4a + 2a + 3 = 0
= -32a^5 + 32a^5 - 2a + 3 = 0
= -2a + 3 = 0
= -2a = - 3
a = 3/2.
Therefore the value of a = 3/2.
Hope this helps!
Given f(x) = x^3 - 2mx^2 + 16
Given that x + 2 is a factor of f(x).
= > x + 2 = 0
= > x = -2.
Plug x = -2 in f(x), we get
= > (-2)^3 - 2m(-2)^2 + 16 = 0
= > -8 - 8m + 16 = 0
= > 8 - 8m = 0
= > 8 = 8m
= > m = 1.
Therefore the value of m = 1.
(20)
Given f(x) = x^5 - 4a^2x^3 + 2x + 2a + 3.
Given that x + 2a is a factor of f(x).
= > x + 2a = 0
= > x = -2a.
Plug x = -2a in f(x), we get
= > f(-2a) = (-2a)^5 - 4a^2(-2a)^3 + 2(-2a) + 2a + 3 = 0
= -32a^5 + 32a^5 - 4a + 2a + 3 = 0
= -32a^5 + 32a^5 - 2a + 3 = 0
= -2a + 3 = 0
= -2a = - 3
a = 3/2.
Therefore the value of a = 3/2.
Hope this helps!
siddhartharao77:
:-)
where is answer 19
U asked only 20th question
sorry
I forgot to write question 19
Wait for 2 minutes..I will solve 19th also
oh thank you
Done..Check your answer now
ok
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Please see the attached file!
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Please see the attached file!
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