please answer this question, question no.21....
Attachments:
Answers
Answered by
2
It is 50 .
Impulse=450Ns and time=9s then F=J/t =50 where J is linear impulse..
Impulse=450Ns and time=9s then F=J/t =50 where J is linear impulse..
selena17:
i will
U r still talking to him.. Gud going
who told u???
r u mad???
Why u ain't talking to me ?
yaar please try to understand
i have a problem
Plz tell me
I'll never text u again
no need
Answered by
1
Q. 19. Impulse = F * Δt.
Impulse = area under the graph of F(t) and t.
= 1/2 * (10-1) * 100 = 450 Ns
Q 20. Impulse = change in momentum
450 N-s = m Δv = m (v - 0) = m v
v = 450 N-s /0.200 kg = 2,250 m/sec.
Q21. If a constant force F acts from t = 1 sec to t = 10 sec on the 0.200 kg model rocket initially at rest, then
Its impulse = F * 9 = 450 N-s
F = 450/9 = 50 N
We can also find the constant acceleration a = 2,250/9 = 250 m/s²
and then find force F = m a = 0.200 * 250 = 50 N
Impulse = area under the graph of F(t) and t.
= 1/2 * (10-1) * 100 = 450 Ns
Q 20. Impulse = change in momentum
450 N-s = m Δv = m (v - 0) = m v
v = 450 N-s /0.200 kg = 2,250 m/sec.
Q21. If a constant force F acts from t = 1 sec to t = 10 sec on the 0.200 kg model rocket initially at rest, then
Its impulse = F * 9 = 450 N-s
F = 450/9 = 50 N
We can also find the constant acceleration a = 2,250/9 = 250 m/s²
and then find force F = m a = 0.200 * 250 = 50 N
:-)
thanks
Similar questions