Question

please answer this question question no.3​

Answer 1

Let first angle Be A ,Second angle be B and third angle be C.

Given. 3A=4B=6C

By angle sum property of a triangle,

A +B+C=180°

A=2C

B=3C/2

So 2C + 3C/2 + C=180°

=>9C=360°

=>C=40°

=>A=2×40=80°

B=3×40/2=60°

Hence A=80°,B=60°,C=40°

Hope it Helps...

Regards,

Leukonov/Olegion.