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Answer:theta =0,pi,2pi
Step-by-step explanation:
1-sintheta/1+sintheta =1-sin^2theta/cos^2theta
1-sintheta/1+sintheta =sec^2theta - tan^2theta
(sec^2theta-tan^2theta =1) so
1-sintheta /1+sintheta =1
1-sintheta =1+sintheta
So sintheta must be zero
So theta =0,pi,2pi
After substituting the value....
The equation will be proved
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HEY! SOLUTION IS GIVEN IN THE ATTACHMENT
HOPE IT HELPS :)
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