Question

please answer this question quick

Answer 1

ℌ℮¥¥Ѧ мї﹩﹩
(ϰ+1/ϰ)³=ϰ³+1/ϰ³+3×ϰ×1/ϰ(ϰ+1/ϰ)
(ϰ+1/ϰ)³ =110 +3(ϰ+1/ϰ)
ʟᴇᴛ (ϰ+1/ϰ) ♭℮ Ѧ
Ѧ³=110+3Ѧ
Ѧ³-3Ѧ-110=0
℘ʊ† Ѧ=5 
⇒ 5³− 3(5) −110 =125 −15 −110=0 
Hence (a − 5) is a factor. 
On dividing (a3 − 3a −110) with (a − 5) we get the quotient as (a2+5a+22) ∴ a3 − 3a −110 = (a − 5)(a2+5a+22) = 0 
Hence (a − 5) = 0 and (a2+5a+22) ≠ 0 ⇒(x+1/x) − 5=0 ∴ (x+1/x) = 5  
ℌ◎℘℮ ї† ℌ℮ℓ℘﹩