Math, asked by AshKetchum49, 1 year ago

please answer this question quickly

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Answered by Brainlyd
1

Answer:

11=a+b-c

Step by step explanation:

Using the identity: (a+b-c)²= (a²+b²+c²)+ 2(ab-bc-ca)

(a+b-c)²= 89+ 2(16)

=89+32

=121=(a+b-c)²

√121=a+b-c

=11=a+b-c

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