please answer this question quickly
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Answer:
11=a+b-c
Step by step explanation:
Using the identity: (a+b-c)²= (a²+b²+c²)+ 2(ab-bc-ca)
(a+b-c)²= 89+ 2(16)
=89+32
=121=(a+b-c)²
√121=a+b-c
=11=a+b-c
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