Question

Please answer this question quickly

Answer 1

Let a/r, a and ar are the root of 3x³‐26x²+52x‐24=0

Thus products of roots =24/3=a³=>a=2

And sum of roots = 26/3=2/r+2+2r

=>1/r+r=10/3

⇒3r²−10r+3=0

⇒(3r−1)(r−3)=0

=>r =1/3,3

Hence the roots are 2/3, 2, 6.