Question

please answer this question seriously its urgent (please give full explanation) ​

Answer 1

Answer:

Step-by-step explanation:

So, you start of with the equation:

Eq 1). 23x-29y=98

Eq 2). 29x-23y=110

on subtracting Eq2 from Eq 1, we get

23x-29y=98

-29x+23y=-110

=

-6x+6y=-12

Since the whole equation is divisible by 6,Dividing LHS and RHS by six, we get,

-x+y=2 or y-x=2

Answer 2

Step-by-step explanation:

23x - 29y = 98 (1)

29x - 23y = 110 (2)

Subtract (1) from (2)

29x - 23x - 23y + 29 y = 110 - 98

6x + 6y = 12

6(x + y) = 12

x + y = 2

x = 2 - y (3)

Substitute the value of x in (1)

23(2 - y) - 29 y = 98

46 - 23y - 29y = 98

-52y = 42

y =

$- \frac{42}{52} = - \frac{21}{26}$

Substituting the value of y in (3)

x =

$2 + \frac{21}{26} = \frac{52 + 21}{26} = \frac{73}{26}$