Question

Please answer this question soon. I need it real quick as my exam is tmrw

Answer 1

By conservation of momentum:

m1u1+m2u2 = m1v1 + m2v2

Here after collision , masses stick together,

So,

M1u1+m2u2=(m1+m2)v

m1=1kg

m2=5kg

u1=10m/s

u2=0

Substituting:

(1)(10)+(5)(0)=(1+5)v

10=6v

v=10/6

v=1.666m/s

Combined velocity is 1.67 m/s

Answer 2

The diagram you have drawn is right.

Now consider the after the collision, the two objects become one and the mass of the combined object is 6kg.

Then, using Conservation of Linear

Momentum,

(1kg * 10) + (5*0) = 6*v

10 + 0 = 6v

v = 10/6 = 5/3 = 1.66ms^-1