Math, asked by TanviMisal, 1 month ago

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Answered by webstararijit
4

1

Using the formula

a³ - b³ = (a - b)(a² +ab + b²)

- (2x + 3y)³ - (2x - 3y)³

= [(2x + 3y) - (2x - 3y)][(2x + 3y)² + (2x +

3y) (2x-3y) + (2x - 3y)²]

= [2x + 3y - 2x + 3y][4x² + 12xy + 9y² + 4x²-9y² +4x²-12xy +9y²]

= 6y(12x² +9y²)

= 72x²y + 54y³

Answered by kamalhajare543
20

Answer:

Question 1

 \sf \implies\sf \: (2x+3y)^3 −(2x−3y)^3

 \sf \: = {8x}^{3} + {27y}^{3} + 18xy + (2x + 3y) - {8x}^{3} - {27y}^{3} - 18xy + (2x - 3y)

 \sf \: = (2x + 3y) - (2x - 3y)

\sf \implies \sf \bold{2x + 3y - 2x + 3y}

\sf \implies \sf \:  \red{ 3y + 3y = 6y}

Hence This is Answer.

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