Question

Please answer this question

Std 12th
Ch. 2 Electrostatic potential and capacitance ​

Answer 1

C₂ and C₃ are in series, so C₂₃ = 100pF

C₁ , C₂₃ and C₄ are in parallel, so net capacitance, C₁₂₃₄ = 300pF

Since, the the voltage across all parallel branches are same, voltage across C₁ and C₄ ie, V₁ = V₄ = 300V. Hence charge across the same, Q₁ = Q₄= 3 × 10⁻⁸

Since, voltage across C₂₃ = 300 V, charges across the capacitors in series will be same, but voltage across capacitors in series will not be. Therefore, net charge across C₂₃, Q₂₃ = 3 × 10⁻⁸

Here voltage across C₂ and C₃ will be same because C₃ = C₂

Therefore, voltage = Q/C = V₂ =V₃ = 150V