please answer this question step by step
I request you
Attachments:
Answers
Answered by
0
Given,
Ratio of Cu & Zn = 9 : 5
Given weight of Cu = 48.6 gms
Say weight of Zn = x
As per ratio and proprtion,
Ratio of Weight of Cu & Zn :: Ratio of Cu & Zn
48.6 : x :: 9 : 5
Product of Extremes = Product of mean
48.6 × 5 = 9x
=> x = (48.6×5)/9
=> x = 27
The weight of Zn = 27 gms
Ratio of Cu & Zn = 9 : 5
Given weight of Cu = 48.6 gms
Say weight of Zn = x
As per ratio and proprtion,
Ratio of Weight of Cu & Zn :: Ratio of Cu & Zn
48.6 : x :: 9 : 5
Product of Extremes = Product of mean
48.6 × 5 = 9x
=> x = (48.6×5)/9
=> x = 27
The weight of Zn = 27 gms
Answered by
0
=========================================
♠ Let the common ratio of weights of copper and zinc be 'x'.
♦ Then,
weight of copper = 9x
weight of zinc = 5x
♦ But, A / Q, weight of copper = 48.6 g
=>>> 9x = 48.6
=> x = 48.6/9
=> x = 5.4
♥ •°•
Weight of copper = 9x = 9(5.4) = 48.6 g
Weight of zinc = 5x = 5(5.4) = 27 g
=========================================
Thank you.. ^_^
Similar questions