Math, asked by ap1703502, 1 month ago

please answer this question that is in picture .

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ap1703502: is no one able to solve this equation?

Answers

Answered by satveer2410a

(3x-x-2)/3=(4-x-3)/4

(2x-2)/3=(1-x)/4

8x-8=3-3x

8x+3x=3+8

11x=11

x=1

satveer2410a: ye galat h kya

ap1703502: Yes answer sheet me khuch aur hai

satveer2410a: ohh sorry vo (-) ki mistake h.

satveer2410a: ruko jara

ap1703502: 13\11 aaa rha hai

satveer2410a: ye correct h bhai mere bhi yhi aarha h

satveer2410a: vo jaldbaji me dhyan nhi rha

ap1703502: method post kardo

ap1703502: please

satveer2410a: ok dusre vale question ke answer me karta hu

Answered by MrImpeccable

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

Given:

$x - \dfrac{x-2}{3} = 1 - \dfrac{x-3}{4}$

To Find:

Value of x

Solution:

$\implies x - \dfrac{x-2}{3} = 1 - \dfrac{x-3}{4} \\ \\ \implies \dfrac{3x - x + 2}{3} = \dfrac{4 - x + 3}{4} \\ \\ \implies \dfrac{2x + 2}{3} = \dfrac{7 -x}{4} \\ \\ \implies 4(2x + 2) = 3(7 - x) \\ \\ \implies 8x + 8 = 21 - 3x \\ \\ \implies 8x + 3x = 21 - 8 \\ \\ \implies 11x = 13 \\ \\ \bold{\implies \dfrac{13}{11}} \\$

Hope It Helps!!

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