Question

Please answer this question
The answer is 10 but I can't arrive at that answer

Answer 1

Step-by-step explanation:

The highest frequency is 16 and it lies in 30-50.So, modal class is 30-40.

MODE=16

Therefore, Frequency,(f1)= 16

Frequency,(f2)=12

Frequency,(f0)= x

Lower limit, l=30

Class size= 10

: We know that,

MODE = L+(F1-F0/ 2F1 -F2- F0) ×H

36 = 30+(16-x/ 32-12-x)×10

36 = 30+(16-x/ 20-x)×10

6 =(16-x/20-x)×10

6/10 = 16-x/ 20-x

6(20-x) = 10(16-x)

120-6x = 160-10x

40-4x =0

4x =40

x =40/4

x =10

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