Question

please answer this question( The answer with best explanation will earn Brainliest)​

Answer 1

Given,p(x)=

$6x \times 4 - {13}^{3} - 34x ^{2} + 47x + 30$

Two zeros of p(x)= -2 ,3

=(x+2)(x-3)

=x square-3x+2x-6

=x square -1x-6=g(x)

Now divide p(x) with g(x)

x square-x-6) 6x^4 - 13x cube-34x square+47x+30 (6xsquare -7x -5

6x^4 -6x cube -36x square

(-)_(+)_(+)__________

0 -7x cube 2x square +47x +30

-7xcube +7x square +42x

(+)______(-)________(-)

0 -5x square+ 5x +30

-5x square+5x +30

(+)________(-)_(-)_

[ 0 ]

Now take q(x),=6x square -7x-5

spiting of the middle terms,

= 6x square +3x-10x - 5

=3x(2x-1)(3x-5)

x = -1/2,5/3

Therefore, the other two zeros of p(x)= -1/2,5/3

HOPE YOU LIKE IT AMUL BABY.

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