Please answer this question. The dimensions of a cuboid is in the ratio4:3:2. If the total surface area of the cuboid is 4212 sqm
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let L be 4x and B be 3x and H be 2x
total surface area = 4212 sq m
2(4x*3x + 3x*2x + 2x*4x ) = 4212
2( 12x^2 + 6x^2 + 8x^2 ) = 4212
2 × 26x^2 = 4212
x^2 = 4212 / (2*26)
x^2 = 81x^2 = 9x^2 x=9
length = 4x = 4×9 = 36m
breadth = 3x = 3×9 = 27m
height = 2x = 2×9 = 18 m
Volumeof cuboid = L*B*H
36*27*18 = 17496 m^3
total surface area = 4212 sq m
2(4x*3x + 3x*2x + 2x*4x ) = 4212
2( 12x^2 + 6x^2 + 8x^2 ) = 4212
2 × 26x^2 = 4212
x^2 = 4212 / (2*26)
x^2 = 81x^2 = 9x^2 x=9
length = 4x = 4×9 = 36m
breadth = 3x = 3×9 = 27m
height = 2x = 2×9 = 18 m
Volumeof cuboid = L*B*H
36*27*18 = 17496 m^3
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