Question

Please answer this question

The sum of three numbers is 66. The second number is twice the first and six less than the third. Find the numbers.

Answer 1

Step-by-step explanation:

Let the required number be x then,

x + 2x + (2x + 6) = 66

=> 3x + 2x + 6 = 66

=> 5x = 66 - 6

=> 5x = 60

=> x = 60/5

Hence, x = 12

Verification :-

If x is 12 then,

12 + 12 × 2 + (12 × 2 + 6) = 66

=> 12 + 24 + 30 = 66

=> 36 + 30 = 66

=> 66 = 66 [L.H.S = R.H.S]

The three number should be :-

x = 12

2x = 24

2x + 6 = 30

Answer) Hence, the three numbers are 12, 24 and 30.

Answer 2

Answer:

• Three numbers are 12, 24 and 30.

Step By Step Explanation:

Given:

• Sum of three numbers = 66.
• Second Number is twice the first.
• Second Number is 6 less than third number.

To Find:

• Three numbers.

Let First number be 'x'.

Now, according to question

It is given that second number is twice of first number.

=> Second number = 2x

And, it is also given that second number is 6 less than third number.

=> Second number = Third number - 6

=> 2x = Third number - 6

=> Third number = 2x + 6

Now, we know that sum of three number is 66.

=> First number + second number + third number = 66

=> x + 2x + 2x + 6 = 66

=> 5x = 66 - 6

=> 5x = 60

=> x = 60/5

=> x = 12

Hence:

• First number = 12
• Second number = 2x = 24
• Third number = 2x + 6 = 30

Verification:

=> Sum of three numbers = 66

=> 12 + 24 + 30 = 66

=> 66 = 66

Hence Proved!!!