Question

Please answer this question..

the velocity position graph of a particle moving in a straight line along x-axis is given below.Acceleration of particle at x =2m is​

Answer 1

a=dv/dx

=d2x²/dx

=4x

therefore acceleration at x=2

a=4*2

=8 m/s²

option 1

Answer 2

Answer:

a= 64 m/s²  

Explanation:

Given that

v= 2 x²

We know that if velocity is varying with distance x the acceleration given as

$a=v\dfrac{dv}{dx}$

v= 2 x²

$\dfrac{dv}{dx}=4x$

At x= 2 m

v= 2 (2)²= 8 m/s

$\dfrac{dv}{dx}=4x$

$\dfrac{dv}{dx}=8s^{-1}$

$a=v\dfrac{dv}{dx}$

$a=8\times 8$

a= 64 m/s²