Math, asked by sapnakumare27271, 2 months ago

please answer this question this is not correct answer others wise report your answer​

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Answered by Nihar1729
2

Answer:

1. 5x - 2y - 8 = 0 -------------------------------- (i)

2. 2x - 5y - 12 = 0 -------------------------------(ii)

Now, in eq(i) ,

     5x - 2y - 8 = 0

  => 5x = 8 + 2y

  => x = (8+ 2y ) /5 ---------------------------------(iii)

Now putting  the value of x from eq(III) in eq(ii), we get,

     2x - 5y - 12 = 0

  => 2[( 8 + 2y )/5] - 5y = 12

  => [(16 + 4y) /5 ] - 5y = 12

  => 16 + 4y - 25y = 60

  => -21y = 44

  => y = -44/21 --------------------------------------------- (iv)

Now ,

  putting the value of y in eq(iii), we get

          x = [8 + 2 ( -44/21 )]/5

        => x = (168 - 88)/105

        => x = 80/105

        => x = 16/21

∴ x = 16/21 and y = -44/21   (Ans.)

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Answered by Mysteryboy01
1

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